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2026.09.05 16:00

121/1000, derivative of sin^-1(x), implicit differentiation

  • bprp calculus b… 27일 전 2026.09.05 16:00 인기
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    @vikramrawat526…  27일 전

    Day one to one

    2026-09-05 19:21

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    @ImadAjjaj  27일 전

    121?

    2026-09-05 17:41

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    @BassemFanari  27일 전

    How to find d/dx (sin⁻¹ x) without using θ (or any other variable)
    ∵  sin(sin⁻¹ x) = x
    ∴  d/dx sin(sin⁻¹ x) = 1
    Differentiating:
    ⇒  cos(sin⁻¹ x)⋅d/dx (sin⁻¹ x) = 1
    ⇒  d/dx (sin⁻¹ x) = 1/cos(sin⁻¹ x)
    ⇒  d/dx (sin⁻¹ x) = 1/√(1–sin²(sin⁻¹ x))
    ⇒  d/dx (sin⁻¹ x) = 1/√(1–x²)

    2026-09-05 16:54

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    @sarin_5063  27일 전

    The reason why cos theta = sqrt(1-x^2) and not +-sqrt(1-x^2):

    When you define theta = arcsin x, the range of possible values of theta becomes [-pi/2, pi/2].
    For any value of theta in this range, cos theta >= 0. Therefore, the possibility that cos theta = -sqrt(1-x^2) is ruled out.

    (This is also the same reason as to why you do not use absolute values when doing trig subs in integration)

    2026-09-05 16:54

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    @crankykransky2…  27일 전

    Now do it by first principles

    2026-09-05 16:13

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    @OyatilloToshma…  27일 전

    Day 121?

    2026-09-05 16:07

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    @surenazand  27일 전

    Thank you I learned so much ❤

    2026-09-06 03:16

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    @Antonino-f1i  27일 전

    Perfect ???

    2026-09-06 02:43

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    @_zelatrix  27일 전

    What's stopping me saying that 1/cos x = sec x at the end?

    2026-09-05 21:51

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    @tionggeegoh986…  24일 전

    this differentiation is only for |x|<½π hence cos theta >0 ie cos theta =√(1-x²)

    2026-09-08 15:52