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Mathematics ❤️

• SMP~MATHS 1일 전 2026.08.10 20:59 인기
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이전글Questão para não zerar #matematica2026.08.11
다음글Olympiad mathematics challenge2026.08.11
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@AayushRaj-i3e6… 　1일 전

Answer to this question should be m E [ 200, infinity)

2026-08-11 02:50

[ytcid:Ugzy5kE_RscwDALQGKd4AaABAg] Answer to this question should be m E [ 200, infinity)



@AbhinavDeb-t2h 　1일 전

Sir,plz explain and solve this question,find the number of solutions of sin (πx)+x^2 +x+1=0,using class 11 trigonometry concepts,I tried to solve it but I was unable if we draw the graph we see that there are two unique intersecting points i.e,two solutions but how to show it without graph by using trigonometry, algebra,etc,we are  easily able to show 0≤x≤2 ,and x=1 is a trivial solution,I was also able to show that there exist no solution for 0<x<1,and x=0,2 (the endpoints) don't satisfy the equation,also we can easily see that for 0<x<2 , solution may exist,but how to proceed from here,this is a pre dpp question of vibrant academy

2026-08-11 00:10

[ytcid:UgyjndHynGi9vHX3ort4AaABAg] Sir,plz explain and solve this question,find the number of solutions of sin (πx)+x^2 +x+1=0,using class 11 trigonometry concepts,I tried to solve it but I was unable if we draw the graph we see that there are two unique intersecting points i.e,two solutions but how to show it without graph by using trigonometry, algebra,etc,we are easily able to show 0≤x≤2 ,and x=1 is a trivial solution,I was also able to show that there exist no solution for 0<x<1,and x=0,2 (the endpoints) don't satisfy the equation,also we can easily see that for 0<x<2 , solution may exist,but how to proceed from here,this is a pre dpp question of vibrant academy



@thedestructive… 　1일 전

I have proved all angles in a triangle is 90 not 180 check it

2026-08-10 23:40

[ytcid:UgzJr7Moj3U1vmuTrDd4AaABAg] I have proved all angles in a triangle is 90 not 180 check it



@pkenterprise-a 　1일 전

❤❤

2026-08-10 22:34

[ytcid:Ugyhi52eeZZXBcxWKiN4AaABAg] ❤❤



@AayushRaj-i3e6… 　1일 전

Answer is not right .....

2026-08-10 22:08

[ytcid:UgyOf-lWvN_fCTYTyaJ4AaABAg] Answer is not right .....



@pathokerboithe… 　1일 전

Better to use ✓x = 10 + ✓y (from give equation)
Now squaring both side we get, x = 100 + y +20✓y
Or x- 2y = 100 +20✓y - y
Or x-2y = 100 - ( (✓y)² - (2)(✓y) (10) + 10² -10²)
Or, x -2y = 200 - (✓y-10)²
So maximum value of x -2y will be 200.

2026-08-10 22:07

[ytcid:Ugy01eoyrK-KbGfKWE94AaABAg] Better to use ✓x = 10 + ✓y (from give equation) Now squaring both side we get, x = 100 + y +20✓y Or x- 2y = 100 +20✓y - y Or x-2y = 100 - ( (✓y)² - (2)(✓y) (10) + 10² -10²) Or, x -2y = 200 - (✓y-10)² So maximum value of x -2y will be 200.



@Priyodeep-w8x 　1일 전

❤❤

2026-08-10 21:37

[ytcid:UgwgIe9M4M2tlw5PFXB4AaABAg] ❤❤