@RayyanSaeed-pp… 1일 전 2 power 30 Answer 2026-08-11 20:08 [ytcid:UgxowbcwZsB3lQGRqEx4AaABAg] 2 power 30 Answer
@Zuhaib_Artist_… 1일 전 a^m ÷ a^n is a^m-n= 2^10-(-20) = 2^302^30 = 1, 073, 741, 824 2026-08-11 19:33 [ytcid:Ugz4K-WiMkcHkWkS_2d4AaABAg] a^m ÷ a^n is a^m-n = 2^10-(-20) = 2^30 2^30 = 1, 073, 741, 824
@heidiaamodt513… 1일 전 Congratulation to those that find the solution❣️ 2026-08-12 05:52 [ytcid:Ugwh9-9jlopkYNj91JB4AaABAg] Congratulation to those that find the solution❣️
@BouhadidaKaddo… 1일 전 You're brilliant ^+∞ . ❤?❤?❤?❤?............................................ 2026-08-12 00:10 [ytcid:UgzXU731XlWm481LDPR4AaABAg] You're brilliant ^+∞ . ❤?❤?❤?❤?............................................
@dannguyenthi79… 1일 전 Solution: (I got mine and NO use AI)(2¹⁰+2¹¹+...+2²⁰)/[2^(-10)+2^(-11)+...+2^(-20)]=Sigma(2^k; k=10->20)/Sigma[2^(-k); k=10->20]*) 2^(-k)=2^[-30+(30-k)]=2^(-30)*2^(30-k)=> Sigma[2^(-k); k=10->20]=Sigma[2^(-30)*2^(30-k); k=10->20]=2^(-30)*Sigma[2^(30-k); k=10->20]=2^(-30)*(2²⁰+2¹⁹+...+2¹⁰)=2^(-30)*Sigma(2^k; k=10->20)-> Sigma(2^k; k=10->20)/Sigma[2^(-k); k=10->20]=Sigma(2^k; k=10->20)/[2^(-30)*Sigma(2^k; k=10->20]=1/[2^(-30)=2^[-(-30)]=2³⁰ 2026-08-11 22:43 [ytcid:Ugxk4IYQUtE-0LGMByJ4AaABAg] Solution: (I got mine and NO use AI) (2¹⁰+2¹¹+...+2²⁰)/[2^(-10)+2^(-11)+...+2^(-20)] =Sigma(2^k; k=10->20)/Sigma[2^(-k); k=10->20] *) 2^(-k)=2^[-30+(30-k)] =2^(-30)*2^(30-k) => Sigma[2^(-k); k=10->20] =Sigma[2^(-30)*2^(30-k); k=10->20] =2^(-30)*Sigma[2^(30-k); k=10->20] =2^(-30)*(2²⁰+2¹⁹+...+2¹⁰) =2^(-30)*Sigma(2^k; k=10->20) -> Sigma(2^k; k=10->20)/Sigma[2^(-k); k=10->20] =Sigma(2^k; k=10->20)/[2^(-30)*Sigma(2^k; k=10->20] =1/[2^(-30) =2^[-(-30)]=2³⁰
@mariadelcarmen… 1일 전 2^10/2^-20. 2^10-(-20). 2^30. Saludos 2026-08-11 21:53 [ytcid:UgxHNQogqnT0hU_6wuV4AaABAg] 2^10/2^-20. 2^10-(-20). 2^30. Saludos
@Pratibha-h8t 7시간 전 Take a bow sir ✋?✋? 2026-08-13 01:23 [ytcid:UgzyuvnZ2GsAIdBCUN94AaABAg] Take a bow sir ✋?✋?